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Proof step 8 from proof mkDecimal-reduce-scale (previous step)

i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(i0, j).scale = max(0, abs(j) - maxScale(i0)) ⊦ mkDecimal(i / 10, abs(j) - 1).scale = max(0, abs(j) - maxScale(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i % 10 = 0, ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(i0, j).scale = max(0, abs(j) - maxScale(i0)) ⊦ j = 0, i = 0, mkDecimal(i / 10, abs(j) - 1).scale = max(0, abs(j) - maxScale(i))

Proof step 8 from proof mkDecimal-reduce-scale (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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