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Proof step 9 from proof mkDecimal-selectors (previous step)

¬(i % 10 = 0 ∧ i0 ≠ 0 ∧ i ≠ 0), ∀ i1, i0. i→n(i1) < i→n(i) → true → mkDecimal(i1, i0) = mkDecimal(mkDecimal(i1, i0).int, mkDecimal(i1, i0).scale) ⊦ mkDecimal(i, i0) = mkDecimal(i, mkDecimal(i, i0).scale), i % 10 = 0 ∧ i0 ≠ 0 ∧ i ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ i1, i0. i→n(i1) < i→n(i) → true → mkDecimal(i1, i0) = mkDecimal(mkDecimal(i1, i0).int, mkDecimal(i1, i0).scale) ⊦ mkDecimal(i, i0) = mkDecimal(i, mkDecimal(i, i0).scale), i % 10 = 0 ∧ i0 ≠ 0 ∧ i ≠ 0

Proof step 9 from proof mkDecimal-selectors (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information