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Proof step 4 from proof scale-le (previous step)

abs(j) < mkDecimal(i, j).scale, ∀ i0, j. i→n(i0) < i→n(i) → abs(j) < mkDecimal(i0, j).scale → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0 → mkDecimal(i, j).scale = mkDecimal(i / 10, abs(j) - 1).scale
Proof step 6:
¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), abs(j) < mkDecimal(i, j).scale, ∀ i0, j. i→n(i0) < i→n(i) → abs(j) < mkDecimal(i0, j).scale → false ⊦
Proof step 9:
i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, abs(j) < mkDecimal(i / 10, abs(j) - 1).scale, ∀ i0, j. i→n(i0) < i→n(i) → abs(j) < mkDecimal(i0, j).scale → false ⊦

Rule argument

spec: inst: name: scale-rec seq: ⊦ i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0 → mkDecimal(i, j).scale = mkDecimal(i / 10, abs(j) - 1).scale subst: [j, i] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i