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Proof step 11 from proof scale-negate (previous step)

i % 10 = 0 ∧ j ≠ 0, ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ mkDecimal(~ i, j).scale = mkDecimal(i / 10, abs(j) - 1).scale

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i % 10 = 0, ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ j = 0, mkDecimal(~ i, j).scale = mkDecimal(i / 10, abs(j) - 1).scale

Proof step 11 from proof scale-negate (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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