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Proof step 5 from proof scale-negate (previous step)

¬(i % 10 = 0 ∧ j ≠ 0), ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ mkDecimal(~ i, j).scale = mkDecimal(i, j).scale

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ mkDecimal(~ i, j).scale = mkDecimal(i, j).scale, i % 10 = 0 ∧ j ≠ 0

Proof step 5 from proof scale-negate (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information