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Proof step 8 from proof scale-negate (previous step)

¬(i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0), ∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ mkDecimal(~ i, j).scale = abs(j), i % 10 = 0 ∧ j ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
∀ i0, j. i→n(i0) < i→n(i) → true → mkDecimal(~ i0, j).scale = mkDecimal(i0, j).scale ⊦ mkDecimal(~ i, j).scale = abs(j), i % 10 = 0 ∧ j ≠ 0 ∧ i ≠ 0, i % 10 = 0 ∧ j ≠ 0

Proof step 8 from proof scale-negate (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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