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Proof step 10 from proof scale-not-neg (previous step)

i % 10 = 0 ∧ i0 ≠ 0 ∧ i ≠ 0, i % 10 = 0, mkDecimal(i / 10, abs(i0) - 1).scale < 0, ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(i1, i0).scale < 0 → false ⊦ i0 = 0, i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
i % 10 = 0, mkDecimal(i / 10, abs(i0) - 1).scale < 0, ∀ i1, i0. i→n(i1) < i→n(i) → mkDecimal(i1, i0).scale < 0 → false ⊦ i = 0, i0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs