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Proof step 5 from proof test-inc-01 (previous step)

¬(99 % 10 = 0 ∧ 2 ≠ 0 ∧ 99 ≠ 0) ⊦ mkDecimal(99 + 1, mkDecimal(99, 2).scale) = mkDecimal(1, 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2