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Proof step 10 from proof test-01 (previous step)

⊦ 5 = hex("5")

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ str ≠ "" → hex(str) = hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring)
Proof step 12:
"5" ≠ "" ⊦ 5 = hexchar("5".char1) * 16 ^ (n→i(# "5") - 1) + hex("5".rstring)

Rule argument

name: hex-rec rotate: F subst: [str] → ["5"]

Additional information

Used terms: "5"