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Proof step 7 from proof test-01 (previous step)

⊦ 21 = hex("15")

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ str ≠ "" → hex(str) = hexchar(str.char1) * 16 ^ (n→i(# str) - 1) + hex(str.rstring)
Proof step 9:
"15" ≠ "" ⊦ 21 = hexchar("15".char1) * 16 ^ (n→i(# "15") - 1) + hex("15".rstring)

Rule argument

name: hex-rec rotate: F subst: [str] → ["15"]

Additional information

Used terms: "15"