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Proof step 1 from proof BertrandsPostulate (conclusion)

⊦ ∀ i. 0 < i → (∃ j. prime(j) ∧ i < j ∧ j ≤ 2 * i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ ∃ j. prime(j) ∧ i < j ∧ j ≤ 2 * i

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs