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Proof step 31 from proof BertrandsPostulate (previous step)

0 < i ⊦ 2 < i, ∃ j. prime(j) ∧ i < j ∧ j ≤ 2 * i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
0 < i, i ≤ 2 ⊦ ∃ j. prime(j) ∧ i < j ∧ j ≤ 2 * i

Rule argument

Additional information

Used simplifier rules: forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs