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Proof step 3 from proof countFun-pot-01 (previous step)

0 < i2, ∀ i3, i4, i, i0. i→n(i3 - i4) < i→n(i1 - i2) → 0 < i4 → countFun(i4, i3, λ j0. binom_coef(i3, j0 - 1) * i ^ j0 * i0 ^ (i3 + 1 - j0)) = countFun(i4, i3, λ j. i * binom_coef(i3, j - 1) * i ^ (j - 1) * i0 ^ (i3 + 1 - j)) ⊦ countFun(i2, i1, λ j0. binom_coef(i1, j0 - 1) * i ^ j0 * i0 ^ (i1 + 1 - j0)) = countFun(i2, i1, λ j. i * binom_coef(i1, j - 1) * i ^ (j - 1) * i0 ^ (i1 + 1 - j))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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