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Proof step 11 from proof est-4-big-01 (previous step)

0 < i, (2 * i) / 3 < 2 * i % 3, 0 ≤ i, 0 < i % 3, 2 ≤ i % 3, 3 ≤ i, i < 4 ⊦ i = 4

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-basic1 inst: name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [4, i] flags: rewrite

Additional information

Used simplifier rules: lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: 4, i