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Proof step 14 from proof est-4-big-01 (previous step)

j ≤ 2 * i % j, 2 * i < j * j, 2 < i, j ≤ i, (2 * i) / 3 < j, 0 < i, (2 * i) / 3 < 2 * i % j ⊦ j = 3, j = 2

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: est-4-big-02 seq: j ≤ 2 * i % j, 2 < i, j ≤ i, (2 * i) / 3 < j, j ≠ 2, j ≠ 3 ⊦ subst: [j, i] → [j, i] flags: current, []

Additional information

Used terms: j, i