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Proof step 5 from proof est-4-big-01 (previous step)

0 < 3 ∧ 0 ≤ 2 * i, j = 2 ∨ j = 3, (2 * i) / 3 < 2 * i % j, 0 < i, 2 * i < 3 * j, j ≤ i, 2 < i, 2 * i < j * j, j ≤ 2 * i % j ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-ge: ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j); from specification int-mult