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Proof step 8 from proof est-4-big-01 (previous step)

0 < i % 3, 2 ≤ i % 3, 3 ≤ i, i < 5, 0 < i, (2 * i) / 3 < 2 * i % 3, 0 ≤ i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)
Proof step 10:
i ≠ 5 -1, 0 < i % 3, 2 ≤ i % 3, 3 ≤ i, i < 5 -1, 0 < i, (2 * i) / 3 < 2 * i % 3, 0 ≤ i ⊦

Rule argument

spec: int-basic1 inst: name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [5, i] flags: rewrite

Additional information

Used terms: 5, i