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Proof step 3 from proof est-4-big (previous step)

j ≤ 2 * i % j, 0 < i, 2 * i < j * j, 2 < i, j ≤ i, (2 * i) / 3 < j ⊦ (2 * i) / j = 2 * i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j ≤ 2 * i % j, 0 < i, 2 * i < j * j, 2 < i, j ≤ i, (2 * i) / 3 < j, (2 * i) / 3 < 2 * i % j ⊦ (2 * i) / j = 2 * i / j

Rule argument

Additional information

Used simplifier rules: forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs