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Proof step 6 from proof fac-le-one (previous step)

i ≤ 1 ⊦ fac(i) ≤ 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i ≤ 1, i < fac(i), 1 < fac(i), 0 < fac(i) ⊦

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs