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Proof step 12 from proof max_exp-div-not (previous step)

max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4) ⊦ 2 | 4

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ i | j ↔ (∃ i0. i * i0 = j)
Proof step 14:
max_exp(2, 11) = max_exp(2, 2) + max_exp(2, 4) ⊦ ∃ i0. 2 * i0 = 4

Rule argument

spec: int-gcd inst: name: divides seq: ⊦ i | j ↔ (∃ i0. i * i0 = j) subst: [j, i] → [4, 2] flags: rewrite

Additional information

Used terms: 4, 2