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Proof step 19 from proof max_exp-div-not (previous step)

max_exp(2, 11) = 3, 2 | 4, 2 | 11 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1)

Rule argument

spec: int-gcd inst: name: divides-prime seq: ⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1) subst: [j, i] → [11, 2] flags: rewrite

Additional information

Used simplifier rules: prime-11: ⊦ prime(11); from specification int-gcd Used terms: 11, 2