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Proof step 2 from proof max_exp-div-not (previous step)

⊦ ∃ i, j, j0. 0 < j ∧ 0 < j0 ∧ prime(i) ∧ ¬ j0 | j ∧ max_exp(i, j) ≠ max_exp(i, j / j0) + max_exp(i, j0)

User applied rule exists right

And obtained the following new goals

Proof step 3:
⊦ 0 < 11 ∧ 0 < 4 ∧ prime(2) ∧ ¬ 4 | 11 ∧ max_exp(2, 11) ≠ max_exp(2, 11 / 4) + max_exp(2, 4)

Rule argument

pos: right 1 terms: 2, 11, 4 abort: F discard: T computed: F

Additional information

Used terms: 2, 11, 4