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Proof step 1 from proof max_exp-fac-01 (conclusion)

⊦ prime(i) ∧ 0 ≤ j0 ∧ j0 < i → max_exp(i, fac(i + j0)) = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
prime(i), j0 < i, 0 ≤ j0, 0 < i ⊦ max_exp(i, fac(i + j0)) = 1

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs