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Proof step 8 from proof max_exp-fac-gen (previous step)

j2 < i, 1 < i ^ i0, 0 ≤ i0, 0 < i ^ i0, i1 * i + j2 < i ^ i0, prime(i), 0 ≤ j2, 0 < i, 0 < i1 * i + j2, ∀ j0, i2, i0. i→n(j0) < i→n(i1 * i + j2) → prime(i2) ∧ j0 < i2 ^ i0 ∧ 0 < j0 ∧ 0 < i2 ^ i0 ∧ 0 ≤ i0 ∧ 1 < i2 ^ i0 → max_exp(i2, fac(j0)) = Σ countFun(1, i0, λ j1. j0 / i2 ^ j1) ⊦ max_exp(i, fac(i1 * i + j2)) = Σ countFun(1, i0, λ j0. (i1 * i + j2) / i ^ j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ prime(i) ∧ 0 < j ∧ 0 ≤ j0 ∧ j0 < i → max_exp(i, fac(i * j + j0)) = j + max_exp(i, fac(j))
Proof step 10:
¬(prime(i) ∧ 0 < i1 ∧ 0 ≤ j2 ∧ j2 < i), j2 < i, 1 < i ^ i0, 0 ≤ i0, 0 < i ^ i0, i1 * i + j2 < i ^ i0, prime(i), 0 ≤ j2, 0 < i, 0 < i1 * i + j2, ∀ j0, i2, i0. i→n(j0) < i→n(i1 * i + j2) → prime(i2) ∧ j0 < i2 ^ i0 ∧ 0 < j0 ∧ 0 < i2 ^ i0 ∧ 0 ≤ i0 ∧ 1 < i2 ^ i0 → max_exp(i2, fac(j0)) = Σ countFun(1, i0, λ j1. j0 / i2 ^ j1) ⊦ max_exp(i, fac(i1 * i + j2)) = Σ countFun(1, i0, λ j0. (i1 * i + j2) / i ^ j0)
Proof step 20:
prime(i) ∧ 0 < i1 ∧ 0 ≤ j2 ∧ j2 < i, j2 < i, 1 < i ^ i0, 0 ≤ i0, 0 < i ^ i0, i1 * i + j2 < i ^ i0, prime(i), 0 ≤ j2, 0 < i, 0 < i1 * i + j2, ∀ j0, i2, i0. i→n(j0) < i→n(i1 * i + j2) → prime(i2) ∧ j0 < i2 ^ i0 ∧ 0 < j0 ∧ 0 < i2 ^ i0 ∧ 0 ≤ i0 ∧ 1 < i2 ^ i0 → max_exp(i2, fac(j0)) = Σ countFun(1, i0, λ j1. j0 / i2 ^ j1) ⊦ i1 + max_exp(i, fac(i1)) = Σ countFun(1, i0, λ j0. (i1 * i + j2) / i ^ j0)

Rule argument

spec: inst: name: max_exp-fac-rec seq: ⊦ prime(i) ∧ 0 < j ∧ 0 ≤ j0 ∧ j0 < i → max_exp(i, fac(i * j + j0)) = j + max_exp(i, fac(j)) subst: [j0, j, i] → [j2, i1, i] flags: rewrite, current

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: j2, i1, i