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Proof step 3 from proof max_exp-fac-smaller (previous step)

prime(i) ∧ j < i ∧ 0 < j ∧ 0 < i ∧ 1 < i, ∀ j0, i. i→n(j0) < i→n(j) → prime(i) ∧ j0 < i ∧ 0 < j0 ∧ 0 < i ∧ 1 < i → max_exp(i, fac(j0)) = 0 ⊦ max_exp(i, fac(j)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
1 < i, 0 < i, 0 < j, j < i, prime(i), ∀ j0, i. i→n(j0) < i→n(j) → prime(i) ∧ j0 < i ∧ 0 < j0 ∧ 0 < i ∧ 1 < i → max_exp(i, fac(j0)) = 0 ⊦ max_exp(i, fac(j)) = 0

Proof step 3 from proof max_exp-fac-smaller (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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