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Proof step 2 from proof max_exp-mult (previous step)

prime(i), 0 < j, 0 < j0 ⊦ max_exp(i, j * j0) = max_exp(i, j) + max_exp(i, j0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ prime(i) ∧ 0 < j ∧ 0 < j0 → max_exp(i, j * j0) = max_exp(i, j) + max_exp(i, j0)

Rule argument

spec: inst: name: max_exp-mult-01 seq: ⊦ prime(i) ∧ 0 < j ∧ 0 < j0 → max_exp(i, j * j0) = max_exp(i, j) + max_exp(i, j0) subst: [j0, j, i] → [j0, j, i] flags: rewrite, current

Additional information

Used terms: j0, j, i