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Proof step 21 from proof max_exp-not-div (previous step)

prime(i), 0 < j0, 0 < j, ∀ i0, j1, j. i→n(max_exp(i0, j1)) < i→n(0) → prime(i0) ∧ 0 < j1 ∧ 0 < j → max_exp(i0, j * j1) = max_exp(i0, j1) ∨ i0 | j ⊦ max_exp(i, j * j0) = 0, i | j0, i | j

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: max_exp-zero-01 seq: ⊦ ¬ i | j ∧ prime(i) ∧ 0 < j → max_exp(i, j) = 0 subst: [j, i] → [j * j0, i] flags: rewrite, current

Additional information

Used simplifier rules: prime-divides: ⊦ prime(i) → (i | j * j0 ↔ i | j ∨ i | j0); from specification int-gcd%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%zero-gr: ⊦ 0 < i → (0 < i * j ↔ 0 < j); from specification int-mult Used terms: j * j0, i