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Proof step 1 from proof max_exp-pos-01 (conclusion)

⊦ ¬ max_exp(i0, j0) + max_exp(i, j) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
max_exp(i0, j0) + max_exp(i, j) < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs