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Proof step 1 from proof max_exp-pos-02 (conclusion)

⊦ 0 < max_exp(i, j) ↔ max_exp(i, j) ≠ 0

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: max_exp-pos-04: ⊦ ¬ max_exp(i, j) < 0;%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%lel: ⊦ i < i0 ∧ i = i1 → i1 < i0; (forward) from specification oelem[intlista]%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs