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Proof step 1 from proof max_exp-rec (conclusion)

⊦ prime(i) ∧ i | j ∧ 0 < j → max_exp(i, j) = max_exp(i, j / i) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
prime(i), i | j, 0 < j ⊦ max_exp(i, j) = max_exp(i, j / i) + 1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs