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Proof step 1 from proof max_exp-smaller (conclusion)

⊦ prime(i) ∧ 0 < j ∧ j < i → max_exp(i, j) = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: max_exp-zero-02: ⊦ prime(i) ∧ 0 < i0 → (max_exp(i, i0) = 0 ↔ ¬ i | i0);%div-not-ls: ⊦ i < j ∧ 0 < i → ¬ j | i; from specification int-gcd