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Proof step 4 from proof max_exp-zero-02 (previous step)

¬(¬ i | i0 ∧ prime(i) ∧ 0 < i0), prime(i), 0 < i0 ⊦ max_exp(i, i0) = 0 ↔ ¬ i | i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
max_exp(i, i0) = 0, i | i0, 0 < i0, prime(i) ⊦

Rule argument

Additional information

Used simplifier rules: lel: ⊦ i < i0 ∧ i = i1 → i1 < i0; (forward) from specification oelem[intlista]