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Proof step 15 from proof middle-coef-divides-not (previous step)

(fac(2 * i - i) * fac(i)) * i0 = fac(2 * i), 0 ≤ i, 0 < i, prime(j), 2 * i < j, j | i0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 16:
j | fac(2 * i), (fac(2 * i - i) * fac(i)) * i0 = fac(2 * i), 0 ≤ i, 0 < i, prime(j), 2 * i < j, j | i0 ⊦
Proof step 18:
(fac(2 * i - i) * fac(i)) * i0 = fac(2 * i), 0 ≤ i, 0 < i, prime(j), 2 * i < j, j | i0 ⊦ j | fac(2 * i)

Rule argument

fma: j | fac(2 * i)

Additional information

Used formulas: j | fac(2 * i)