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Proof step 10 from proof prime-divides-pot-01 (previous step)

prime(i), i | i0 ^ i1, 0 ≤ i1, ∀ j0, i, i0. i→n(j0) < i→n(i1 + 1) → prime(i) ∧ 0 < j0 → (i | i0 ^ j0 ↔ i | i0) ⊦ i1 = 0, i | i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs