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Proof step 3 from proof prime-divides-pot-01 (previous step)

prime(i) ∧ 0 < j, ∀ j0, i, i0. i→n(j0) < i→n(j) → prime(i) ∧ 0 < j0 → (i | i0 ^ j0 ↔ i | i0) ⊦ i | i0 ^ j ↔ i | i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information