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Proof step 5 from proof prime-divides-pot (previous step)

i * j = i0 ^ (j0 - 1) * i0, prime(i), 0 ≤ j0, 0 < j0 ⊦ i | i0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
j0 = i1 + 1, i * j = i0 ^ i1 * i0, prime(i), 0 ≤ j0, 0 < j0 ⊦ i | i0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j0, 1, i1] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j0, 1, i1