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Proof step 3 from proof prime-fac-divides (previous step)

prime(i) ∧ i < j ∧ 0 < j, ∀ j0, i. i→n(j0) < i→n(j) → prime(i) ∧ i < j0 ∧ 0 < j0 → i | fac(j0) ⊦ i | fac(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information