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Proof step 10 from proof Diffie-Hellman (previous step)

0 ≤ i ∧ 0 ≤ i1 ∧ 0 ≤ i3, prime(j), i < j, i1 < j, i3 < j, 1 < i, 0 < i, 1 < j, 0 < i1, 0 < i3, 0 < j, 0 ≤ i3, 0 ≤ i1 ⊦ i ^ (i1 * i3) |%| j = (i ^ i3) ^ i1 |%| j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
prime(j), i < j, i1 < j, i3 < j, 1 < i, 0 < i, 1 < j, 0 < i1, 0 < i3, 0 < j, 0 ≤ i3, 0 ≤ i1, 0 ≤ i ⊦ i ^ (i1 * i3) |%| j = (i ^ i3) ^ i1 |%| j

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs