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Proof step 3 from proof Lagrange-SumOf4Squares (previous step)

0 < j → Π all_prime_divisors(j) = j, 0 ≤ j ⊦ ∃ i, i0, i1, i2. j = i ^2 + i0 ^2 + i1 ^2 + i2 ^2

User applied rule cut formula

And obtained the following new goals

Proof step 4:
j = 0, 0 < j → Π all_prime_divisors(j) = j, 0 ≤ j ⊦ ∃ i, i0, i1, i2. j = i ^2 + i0 ^2 + i1 ^2 + i2 ^2
Proof step 6:
0 < j → Π all_prime_divisors(j) = j, 0 ≤ j ⊦ j = 0, ∃ i, i0, i1, i2. j = i ^2 + i0 ^2 + i1 ^2 + i2 ^2

Rule argument

fma: j = 0

Additional information

Used formulas: j = 0