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Proof step 20 from proof RSA-decrypt-ij-vars (previous step)

0 ≤ i2 ∧ 0 ≤ i3, gcd(i2, (i - 1) * (i0 - 1)) = 1, 1 < i * i0, 0 < i2, 0 < i, j < i * i0, ≡mod(i2 * i3, 1, (i - 1) * (i0 - 1)), i2 < i * i0, 2 < i0, 2 < i, prime(i0), prime(i), 0 < j, 0 < i3, 0 < i0 ⊦ j = 0, i3 = 0, i = i0, j = j ^ (i2 * i3) |%| (i * i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
gcd(i2, (i - 1) * (i0 - 1)) = 1, 1 < i * i0, 0 < i2, 0 < i, j < i * i0, ≡mod(i2 * i3, 1, (i - 1) * (i0 - 1)), i2 < i * i0, 2 < i0, 2 < i, prime(i0), prime(i), 0 < j, 0 < i0, 0 < i3, 0 ≤ i2 ⊦ j = 0, i3 = 0, i = i0, j = j ^ (i2 * i3) |%| (i * i0)

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs