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Proof step 3 from proof cong-mult-02 (previous step)

⊦ ≡mod(i0, 1, j) → j | abs(i * i0 - i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
≡mod(i0, 1, j) ⊦ j | i * i0 - i

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd