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Proof step 6 from proof cong-mult-02 (previous step)

j | abs(i0 - 1) ⊦ j | i * i0 - i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
j | i0 - 1 ⊦ j | i * i0 - i

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd