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Proof step 13 from proof cong-mult-rew (previous step)

∃ i1. j * i1 = i0 - i2 ⊦ j | i * i0 - i1 ↔ j | i * i2 - i1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
⊦ j | i * (j * i3 + i2) - i1 ↔ j | i * i2 - i1

Rule argument

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs