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Proof step 3 from proof cong-neg (previous step)

⊦ j | abs(~ i - ~ i0) ↔ ≡mod(i, i0, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ j | i0 - i ↔ ≡mod(i, i0, j)

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd%sub-minus: ⊦ ~ i - ~ j = j - i; from specification int-abs