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Proof step 6 from proof cong-neg (previous step)

⊦ j | i0 - i ↔ j | abs(i - i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ j | i0 - i ↔ j | i - i0

Rule argument

Additional information

Used simplifier rules: div-abs-02: ⊦ i | abs(j) ↔ i | j; from specification int-gcd