[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 64 from proof congmod-def-mod-02 (previous step)

i < 0, i0 < 0, i % j < 0, i0 % abs(j) < 0 ⊦ j = 0, i % j = i0 % abs(j) ↔ i % j + j = i0 |%| j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 65:
⊦ j ≠ 0 → i % abs(j) = i % j
Proof step 66:
j ≠ 0, i < 0, i0 < 0, i % j < 0, i0 % j < 0 ⊦ j = 0, i % j = i0 % j ↔ i % j + j = i0 |%| j

Rule argument

spec: int-div inst: name: mod-abs seq: ⊦ j ≠ 0 → i % abs(j) = i % j subst: [j, i] → [j, i0] flags: rewrite

Additional information

Used terms: j, i0