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Proof step 9 from proof congmod-def-mod-02 (previous step)

¬ i % abs(j) < 0, i < 0, i0 < 0 ⊦ i |%| abs(j) = i0 |%| abs(j) ↔ i |%| j = i0 |%| j, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i % abs(j), i0 < 0, i < 0 ⊦ j = 0, i |%| abs(j) = i0 |%| abs(j) ↔ i |%| j = i0 |%| j

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs