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Proof step 10 from proof congmod-def-mod (
previous step
)
j ≠ 0 → (∃ j0. i0 = j * j0 + i0 |%| j), i |%| j = i0 |%| j, 0 < j ⊦ ∃ i1. i = j * i1 + i0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 11
:
i |%| j = i0 |%| j, i0 = j * j0 + i0 |%| j, 0 < j ⊦ j = 0, ∃ i1. i = j * i1 + i0
Rule argument
Additional information