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Proof step 1 from proof congmod-inverse-pos (conclusion)

gcd(i, j) = 1, 0 ≤ i, 0 ≤ j ⊦ ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
gcd(i, j) = 1, 0 ≤ i, 0 ≤ j ⊦ ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs