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Proof step 10 from proof congmod-inverse-pos (previous step)

gcd(i, j) = 1, i0 < 0, ≡mod(i * i0, 1, j), 0 ≤ j, 0 ≤ i ⊦ 1 < j ∧ 1 < i, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

User applied rule cut formula

And obtained the following new goals

Proof step 11:
1 < j, gcd(i, j) = 1, i0 < 0, ≡mod(i * i0, 1, j), 0 ≤ j, 0 ≤ i ⊦ 1 < j ∧ 1 < i, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0
Proof step 16:
gcd(i, j) = 1, i0 < 0, ≡mod(i * i0, 1, j), 0 ≤ j, 0 ≤ i ⊦ 1 < j, 1 < j ∧ 1 < i, ∃ i0. ≡mod(i * i0, 1, j) ∧ 0 ≤ i0

Rule argument

fma: 1 < j

Additional information

Used formulas: 1 < j